Laplace Transform Inverse Problem - 1
Find \( h(t) \) from \( H(s) = \frac{s^2}{s^3 + 4s^2 + 4s} \)
Answer:
\[ h(t) = e^{-2t} - 2t e^{-2t} \]
Discussion
\( Graph: h(t) = e^{-2t} - 2t e^{-2t} \)
\[ h(t) = e^{-2t} - 2t e^{-2t} \]
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